The normality of a solution made by diluting 12 g of H3PO4 with water to produce 250.0 mL of solution is 1.47 eq/L.
The normality of a solution is;
N = Mass of solute in grams/volume of solution in litres × Equivalent weight
Mass of solute = 12 g
volume of solution = 250.0 mL or 0.25 L
Equivalent weight = Molar mass of H3PO4/n
n = Number of hydrogen ions in H3PO4
Equivalent weight = 98 g/mol/3 = 32.7
Substituting values;
N = 12/0.25 × 32.7
N = 1.47 eq/L
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