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hents
Part E
Calculate the amount of heat lost by the object(s) after being transferred from cup 1 to cup 2. Remember that a
decrease in temperature is a negative change. Use the data recorded in parts A and C and the formula for heat
transfer, Q = mCAT.
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josephszott1

Answer:

2060.775 J

Explanation:

From the question given above, we obtained the following data:

Specific heat capacity (C) = 0.129 J/g°C

Mass (m) = 355 g

Initial temperature (Tᵢ) = 95 °C

Final temperature (Tբ) = 140 °C

Heat (Q) tranfered =?

We can calculate the amount of heat transferred by using the following formula:

Q = mC(Tբ – Tᵢ)

Q = 355 × 0.129 (140 – 95)

Q = 45.795 × 45

Q = 2060.775 J

Thus, 2060.775 J of energy was transferred.

Explanation:

Hope this helps:)

Lanuel

Based on the calculations, the quantity of heat lost by the object is equal to 2060.775 Joules.

How to calculate the amount of heat lost?

Based on the data recorded in parts A and C, we obtained the following parameters:

  • Specific heat capacity (c) = 0.129 J/g°C
  • Mass (m) = 355 grams.
  • Initial temperature (T₁) = 95°C
  • Final temperature (T₂) = 140°C

Next, we would calculate the quantity of heat lost by using the following formula:

Q = m × c ×(T₂ - T₁)

Q = 355 × 0.129 (140 - 95)

Q = 45.795 × 45

Q = 2060.775 Joules.

Read more on heat capacity here: brainly.com/question/16559442

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