A hiker is at the bottom of a canyon facing the canyon wall closest to her. She is 280.5 meters from the wall and the sound of her voice travels at 340 m/s at that location. How long after she shouts will she hear her echo? (Be careful to consider why echoes happen.)

Respuesta :

Answer:

4.80 seconds

Explanation:

The velocity of sound is obtained from;

V= 2d/t

Where;

V= velocity of sound = 329.2 ms-1

d= distance from the wall = 790.5 m

t= time = the unknown

t= 2d/V

t= 2 × 790.5/ 329.2

t= 4.80 seconds

The time is taken by the sound to reach the hiker will be  t= 4.80 seconds

What is sound velocity?

The sound velocity is defined as the distance traveled by the sound wave in a particular direction with respect to time.

The velocity of sound  is given by the formula:

[tex]V=\dfrac{2d}{t}[/tex]

Here;

V= velocity of sound = 329.2  [tex]\frac{m}{s^2}[/tex]

d= distance from the wall = 790.5 m

t= time = the unknown

The time will be calculated as:

[tex]t=\dfrac{2d}{V}[/tex]

[tex]t=\dfrac{2\times 790.5}{329.2}[/tex]

[tex]t=4.80\ seconds[/tex]

Hence the time is taken by the sound to reach the hiker will be  t= 4.80 seconds

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