Answer:
(hope this helps can I pls have brainlist (crown))
Step-by-step explanation:
Morgan could work 6 hours lifeguarding and 3 hours walking dogs.
the total number of hours worked in both jobs,
x+y
x+y, must be less than or equal to 11
solve inequalities for y
x+y≤11
y≤11−x
Morgan makes $19 per hour lifeguarding, so in x hours she will make
19x dollars. Morgan makes $6 per hour walking dogs, so in
y hours she will make 6y dollars. The total amount earned 19x+6y
19x+6y must be greater than or equal to
$120
solve inequalities for y
19x+6y≥120
6y≥120−19x
y≥20-19/6x
