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An envelope is 6 in. wide and 4 in. high. Will a card with an 8 in. diagonal fit in it? Identify the correct explanation.

A) Because 7.2 < 8, it is possible that the card fits in the envelope.
B) Because 8.9 > 8, it is possible that the card fits in the envelope.
C) Because 7.2 < 8, it is NOT possible that the card fits in the envelope.
D) Because 8.9 > 8, it is NOT possible that the card fits in the envelope.

Respuesta :

First we have to find the diagonal of the card. We do this by using the Pythagoras theorem: A^2 = b^2 + c^2
= 6^2 + 4^2
=36 + 16
= 52
A^2= 52
Sqrt A^2 = sqrt 52
A = 7.2
Since the envelopes diagonal is 7.2 inches and the card’s diagonal is 8 inches and 7.2<8. Your answer is c)

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