Calculate the length of the circumference inscribed in the ABCD trapezium using the data shown in the figure
i need help :(
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From the given figure,
Subtracting AB and DC, so,
[tex]6 - 3 = 3 \: cm[/tex]
As we know that :-
[tex]d = \sqrt{ {5}^{2} - {3}^{2} }[/tex]
[tex]→d = 4 π cm[/tex]
Since:-
[tex]c = πd[/tex]
[tex]c = 4πd[/tex]
So, Answer is 4 π d