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Consider the following chemical reaction.
3 Zn(C₂H₃O₂)₂(aq) + 2 Na₃PO₄(aq) → 6 NaC₂H₃O₂(aq) + Zn₃(PO₄)₂(s)

A chemist makes a solution of zinc acetate by dissolving 20.5 g Zn(C₂H₃O₂)₂ in 105 mL H₂O. What is the concentration of this zinc acetate solution?

Respuesta :

Eduard22sly

The concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M

  • We'll begin by calculating the number of mole in 20.5 g of Zn(C₂H₃O₂)₂

Mass of Zn(C₂H₃O₂)₂ = 20.5 g

Molar mass of Zn(C₂H₃O₂)₂ = 65 + 2[(12×2) + (3×1) + (16×2)]

= 65 + 2[59]

= 183 g/mol

Mole of Zn(C₂H₃O₂)₂ =?

Mole = mass / molar mass

Mole of Zn(C₂H₃O₂)₂ = 20.5 / 183

Mole of Zn(C₂H₃O₂)₂ = 0.112 mole

  • Finally, we shall determine concentration of Zn(C₂H₃O₂). This can be obtained as follow:

Mole of Zn(C₂H₃O₂)₂ = 0.112 mole

Volume = 105 mL = 105 / 1000 = 0.105 L

Concentration of Zn(C₂H₃O₂)₂ =?

Concentration = mole / Volume

Concentration of Zn(C₂H₃O₂)₂ = 0.112 / 0.105

Concentration of Zn(C₂H₃O₂)₂ = 1.067 M

Therefore, the concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M

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