9514 1404 393
Answer:
- (f×g)(x) = 2x^2 +2x
- (f×g)(x) = 6y^2 -11y -35
Step-by-step explanation:
The distributive property applies.
1. (fg)(x) = f(x)·g(x) = (2x)·(x +1)
(f×g)(x) = 2x^2 +2x
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2. (fg)(x) = f(x)·g(x) = (2y -7)·(3y +5) = 2y(3y +5) -7(3y +5)
(f×g)(x) = 6y^2 -11y -35
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Additional comment
Please note in problem 2 that the function argument is x and the variable in the given expressions is y. This means the function value is exactly and only 6y^2 -11y -35 for any value of x. It does not change when x changes. (We suspect a typo.)
