a) What impulse occurs when an average force of the rocket engine is 2.4 x 10^6 N is exerted on the blue origin capsule for 130 s? b) What change in momentum does the capsule undergo? c) If the acceleration of the Blue Origin capsule is 7.65 m/s^2 and the capsule is initially at rest, calculate the final speed v(final) after the engine provides it's impulse for 129 s before separation. (Hint use kinematic eqn. v(final) = v(initial) + a*t and solve for v(final)).

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326150

Answer:

A) 2.4 x 10^6 = 130 s

? = 130 s

B) 2.4 x 130 = 2,400,000

? = 2,400,000

Explanation:

A) 2.4 x 1,000,000 = 130 s

2,400,000 = 130 s

B) 2.4 x 130 = 312

2,400,000 = 312

A. The impulse that occured at the time is 3.12×10⁸ Ns

B. The change in momentum the capsule undergo is 3.12×10⁸ Kgm/s

C. The final speed after the engine provides it's impulse for 129 s is 986.85 m/s

A. How to determine the impulse

From the question given above, the following data were obtained:

  • Force (F) = 2.4×10⁶ N
  • Time (t) = 130 s
  • Impulse (I) =?

I = Ft

I = 2.4×10⁶ × 130

Impulse = 3.12×10⁸ Ns

B. How to determine the change in momentum

  • Impulse = 3.12×10⁸ Ns
  • change in momentum =?

Change in momentum = Ft = impulse

Change in momentum = 3.12×10⁸ Kgm/s

C. How to determine the final speed

  • Initial velocity (u) = 0 m/s
  • Acceleration (a) = 7.65 m/s²
  • Time (t) = 129 s
  • Final velocity (v) =?

v = u + at

v = 0 + (7.65 × 129)

v = 0 + 986.85

v = 986.85 m/s

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