Let X be the number of "no" votes. Suppose that a "yes" or "no" is equally likely. Then, X is a binomial random variable with probability p = 1/2 and n = 11 trials.
i.e. X ~ Binomal (1/2,11).
Then,
[tex]P(X=3)=(\frac{11}{3} )(\frac{1}{2} )^{3} (\frac{1}{2})^{8} =8.05[/tex]%