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A meteor moving 468 km per minute traveling south-to-north direction passed near Earth in 2013. Because the meteor was only 45 m wide and 27,700km above Earth’s surface, it was not visible without a telescope.





Which variables from the passage would identify the velocity of the meteor?


A)468 km per minute and south-to-north direction



B)468 km per minute and 45 m


C)27,700 km and south-to-north direction


D)27,000 km and 45 m

Respuesta :

The correct statement is A Its velocity was 7.8 km/s northward . In fact , the problem says that the meteor was moving at 468 km per minute . We can convert this value into km/s , keeping in mind that there are 60 seconds in one minute : 1 min = 60 : v=468km/min=(468km/min)( 1 60 min/s)=7.8km

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