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1/4x+y = -1
a) Determine the line's x-intercept, algebraically.
b) Determine the line's y-intercept, algebraically.
c) Identify the line's slope.
d) Graph the line using the line's intercepts.

Respuesta :

KittyGirl913

Answer:

a) x int: (-4,0)

b) y int : (0,-1)

c) -(1/4)

d) file uploaded

Step-by-step explanation:

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DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

let's solve :

a.) The equation is :

  • [tex] \dfrac{1}{4} x + y = - 1[/tex]

at point of x - intercept, value of y - coordinate is 0, so let's put y = 0 in the equation to find x - intercept.

  • [tex] \dfrac{1}{4} x + 0 = - 1[/tex]

  • [tex]x = - 1 \times 4[/tex]

  • [tex]x = - 4[/tex]

so, value of x - intercept = -4, the point will be (-4 , 0)

b.) At y - intercept value of x - coordinate is 0, so let's put x = 0 in the equation to find y - intercept.

  • [tex] \dfrac{1}{4} \times 0 + y = - 1[/tex]

  • [tex]y = - 1[/tex]

value of y - intercept = -1, the point will be (0 , -1)

c.) let's find slope :

  • [tex] \dfrac{y2 - y1}{x2 - x1} [/tex]

  • [tex] \dfrac{0 - ( - 1)}{ - 4 - 0} [/tex]

  • [tex] - \dfrac{1}{4} [/tex]

d.) Let's graph the line using points (0 , -1) and (-4 , 0)

graph in attachment ~

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