Sixteen percent of people spend more than 86 minutes watching TV shows on a popular streaming service.
Given that P(z > z*) = 16%, mean (μ) = 71, standard deviation (σ) = 15
P(z > z*) = 1 - P(z < z*) = 16%
1 - P(z < z*) = 0.16
P(z < z*) = 0.84
From the normal distribution table, this corresponds with a z score of 1. Hence:
[tex]z*=\frac{x-\mu}{\sigma} \\\\1=\frac{x-71}{15} \\\\x-71=15\\\\x=86[/tex]
Sixteen percent of people spend more than 86 minutes watching TV shows on a popular streaming service.
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