Answer:
AC = [tex]\sqrt{105}[/tex]
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is
AC² + BC² = AB²
AC² + 4² = 11²
AC² + 16 = 121 ( subtract 16 from both sides )
AC² = 105 ( take square root of both sides )
AC = [tex]\sqrt{105}[/tex] ≈ 10.25 cm ( to 2 dec. places )
