QUESTION 27
The treatment cost of a certain medical condition is modelled by one insurance company as a normal random variable
with a mean of R775 and standard deviation of R150. What is the probability that a single treatment will cost less than
R1 000?

Respuesta :

Z-score can be defined as the distance of a given mean value from its data point.  Z-score can also be referred to as the standard score.

The probability that a single treatment will cost less than R1000 is 0.9332

We can solve this question using the z-score formula

The formula for z-score is given as:

z = (x-μ)/σ,

where:

Raw Score, x = R1000

Population Mean, μ = R775

Standard Deviation, σ = R150

Hence:

z = 1000 - 775 / 150

z = 1000 - 775 / 150

z = 1.5

Using the Z -score table to find the probability, the probability that a single treatment will cost less than  R1000, which means P(x<1000) is givens as:

P(x<1000) = 0.93319

Approximately to 4 decimal places: 0.9332

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https://brainly.com/question/12367671