Using divisibility concepts, it is found that 33 cards will have their red side facing up.
From 1 to 100, there are [tex]\frac{100}{2} = 50[/tex] even numbers, that is, 50 numbers which are multiples of 2, which means that 50 cards will have their yellow faces up.
Thus, there are [tex]\frac{99}{3} = 33[/tex] multiples of 3 between 1 and 100.
Of those, 16 are even, so their yellow sides are already up, and the remaining 17 will be turned, so 50 + 17 = 67 cards will have their yellow faces up.
Total of 100 cards, thus 100 - 67 = 33 cards will have their red side facing up.
A similar problem is given at https://brainly.com/question/21416852
Answer:
Step-by-step explanation:
Using divisibility concepts, it is found that 33 cards will have their red side facing up.
A number is a multiple of 2 if it is even.
From 1 to 100, there are even numbers, that is, 50 numbers which are multiples of 2, which means that 50 cards will have their yellow faces up.
A number is a multiple of 3 if the sum of their digits is divisible by 3.
The highest number which is a multiple of 3 below 100 is 99.
Thus, there are multiples of 3 between 1 and 100.
Of those, 16 are even, so their yellow sides are already up, and the remaining 17 will be turned, so 50 + 17 = 67 cards will have their yellow faces up.
Total of 100 cards, thus 100 - 67 = 33 cards will have their red side facing up.
