Respuesta :

mhanifa

Answer:

  • Amir is wrong

Step-by-step explanation:

The function y = x² + 16 is positive for any value of x, hence the graph has no intersection with the x-axis and therefore has no real zero's.

If no zero's, -4 also can't be its zero.

Answer:

No

Step-by-step explanation:

It's law of equations .The number of zeros is also equal to the highest degree of the polynomial/equation.

  • y=x^2+16 has 3 zeros
  • 2 is for x and 1 is for y .

Hence 4 can't be a zero because it won't intercept the x axis.

Let's check

[tex]\\ \sf\longmapsto (-4)^2+16=16+16=32\neq 0[/tex]