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An object near the surface of planet X falls freely from rest and reaches a speed of 12.0 meters per second after it has fallen 14.4 meters. What is the
acceleration due to gravity on planet X?

Respuesta :

nuhulawal20

The  acceleration due to gravity on planet X is approximately 5m/s²

Given the data in the question;

Since the object was initially at rest

  • Initial velocity; [tex]u = 0[/tex]
  • Final velocity; [tex]v = 12.0m/s[/tex]
  • Hight or distance the object fell from; [tex]s = 14.4 m[/tex]
  • Acceleration due to gravity on the planet; [tex]a = ?[/tex]

To determine the acceleration due to gravity, we use the Third Equation of Motion:

[tex]v^2 = u^2 + 2as[/tex]

Where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity and s is the distance.

We make ''a" the subject of the formula

[tex]a = \frac{v^2-u^2}{2s}[/tex]

Now, we substitute our given values into the equation

[tex]a = \frac{(12m/s)^2 - (0m/s)^2}{2\ *\ 14.5m}[/tex]

[tex]a = \frac{144m^2/s^2}{29m}[/tex]

[tex]a = 4.9655m/s^2\\\\a= 5m/s^2[/tex]{approximately}

Therefore, the  acceleration due to gravity on planet X is approximately 5m/s²

Learn more; https://brainly.com/question/6251960

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