The bin containing 382 red, yellow, blue and green balls have a total of 32 green balls.
Let x represent the number of red balls, y represent the number of yellow balls and z represent the number of green balls.
Since ther is a total of 382 balls, hence:
x + y + z = 382 (1)
There is three times as many red balls as yellow balls:
y = 3x
3x - y = 0 (2)
52 more blue balls than yellow balls, hence:
z = y + 52
- y - z = -52 (3)
Solving equations 1, 2 and 3 gives x = 62, y = 186, z = 134
Hence there are 62 red balls, 186 yellow balls and 134 blue balls
Green balls = 62 - 30 = 32 balls
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