A rocket traveling through space with a constant velocity of 10 m/s fires up a booster. The booster accelerates the rocket at a rate of 5 m/s. What distance in meters has the rocket traveled within 12 seconds after the booster is turned on?​

Respuesta :

The distance traveled by the rocket after the given time period is 480 m.

The given parameters;

  • velocity of the rocket, v = 10 m/s
  • acceleration of the rocket, a = 5 m/s²
  • time of motion of the rocket, t = 12 s

The distance traveled by the rocket after the given time period is calculated from the second kinematic equation of as shown below;

s = ut + ¹/₂at²

s = (10 x 12) + (0.5 x 5 x 12²)

s = 120 + 360

s = 480 m

Thus, the distance traveled by the rocket after the given time period is 480 m.

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