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CHEMISTRY HELP NEEDED RIGHT NOW!

1) A piece of metal has a volume of 3.4 mL and a density of 9.4 g/mL. What is its mass?

2) What is the volume of a gold sphere with a mass of 5.00 x 10 (squared 2) grams?

3) if a student finds the density of an object is 10.51 that he believes is gold calculate his percent error

Respuesta :

rspill6

Answer:

Explanation:Density x Volume = Mass

1)  (9.4 g/mL)(3.4 mL) = 31.95g

2)  (19.30 g/ml)*V = 500g  [I assumed a density of gold of 19.30 g/ml]

      V = 25.9g

3)  If the actual density of gold is 19.30 g/ml and he found 10.51 g/ml, then either he is wrong about the sample being gold, or he made an error of [(10.51-19.30)/19.30]*100% or -45.5 %

Eduard22sly

1. The mass of the metal is 31.96 g

2. The volume of the gold is 25.91 mL

3. The percentage error of the student is 45.54%

The density of an object is defined as the mass of the object per unit volume of the object i.e

[tex]Density = \frac{mass}{volume}\\\\\\[/tex]

1. Determination of the mass of the metal.

Volume of metal = 3.4 mL

Density of metal = 9.4 g/mL

Mass of metal =?

Mass = Density × Volume

Mass = 9.4 × 3.4

Mass of metal = 31.96 g

Thus, the mass of the metal is 31.96 g.

2. Determination of the volume of gold.

Mass of gold = 5×10² g = 500 g

Density of gold = 19.3 g/mL

Volume of gold =?

[tex]Volume = \frac{mass}{density} \\\\ Volume = \frac{500}{19.3}\\\\[/tex]

Volume of gold = 25.91 mL

Thus, the volume of the gold is 25.91 mL

3. Determination of the percentage error.

Measured density = 10.51 g/mL

Accepted density = 19.3 g/mL

Absolute error = |Measured – Absolute|

Absolute error = |10.51 – 19.3|

Absolute error = 8.79 g/mL

Percentage error =?

[tex]Percentage error = \frac{Absolute error}{Accepted value } * 100\\\\= \frac{8.79}{19.3} * 100\\\\[/tex]

Percentage error = 45.54%

Therefore, the percentage error of the student is 45.54%

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