Pls show me the work and answerr
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Answer:
B
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
4x + 5y = - 45 ( subtract 4x from both sides )
5y = - 4x - 45 ( divide terms by 5 )
y = - [tex]\frac{4}{5}[/tex] x - 9 ← in slope- intercept form
with slope m = - [tex]\frac{4}{5}[/tex]
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{4}{5} }[/tex] = [tex]\frac{5}{4}[/tex] , then
y = [tex]\frac{5}{4}[/tex] x + c ← is the partial equation
To find c substitute (- 4, - 11 ) into the partial equation
- 11 = - 5 + c ⇒ c = - 11 + 5 = - 6
y = [tex]\frac{5}{4}[/tex] x - 6 → B
Answer:
y=5/4x-6
Step-by-step explanation:
4x + 5y = -45 (this is to be perpendicular to the line)
m=5/4 (where m is the gradient of the line)
Write the formula for equation of a line, we have;
y=mx + b
substituting this
y=mx + b
m=5/4, (-4, -11)
substituting
y=mx + b, we have;
-11=5/4 × (-4) + b
solving the equation, we have;
-11=5/4 × (-4) + b
we have;
-11= -5 + b (this is gotten by cancellation of 4 by itself in this -11=5/4 × (-4) + b)
rearrange the unknown term to the left side of the equation:
-11= -5 + b
we have;
-b= -5 + 11 (b is minus because when it cross of the equality sign it (+ sign)changes to (- sign)
-b= -5 + 11,
given us;
-b=6
substituting
y=mx + b
m=5/4 ,b= -6
therefore, y=mx + b
y=5/4x - c