The percentage of the semicircle shaded section is approximately 23,606 %.
The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:
[tex]r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%[/tex]
[tex]r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%[/tex] (1)
Where:
- [tex]A_{h}[/tex] - Area of the half cross, in square centimeters.
- [tex]A_{s}[/tex] - Area of the semicircle, in square centimeters.
- [tex]r[/tex] - Percentage of the shaded section of the semicircle.
And the percentage of the shaded section is:
[tex]r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100[/tex]
[tex]r \approx 23.606\,\%[/tex]
The percentage of the semicircle shaded section is approximately 23,606 %.
We kindly invite to check this question on percentages: https://brainly.com/question/15469506
