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A compound with a molecular mass of 44.0 grams is found to be 81.82% carbon
and 18.18% hydrogen by mass. Finds its molecular formula. (HINT: Once you get
the mole to mole ratio you will need to multiple both by 3)

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Eduard22sly

The molecular formula of the compound containing 81.82% carbon

and 18.18% hydrogen by mass is C₃H₈

From the question given above, the following data were obtained:

Carbon (C) = 81.82%

Hydrogen (H) = 18.18%

Molar mass of compound = 44 g/mol

Molecular formula =?

We'll begin by calculating the empirical formula of the compound. This can be obtained as follow:

Carbon (C) = 81.82%

Hydrogen (H) = 18.18%

Empirical formula =?

Divide by their molar mass

C = 81.82 / 12 = 6.818

H = 18.18 / 1 = 18.18

Divide by the smallest

C = 6.818 / 6.818 = 1

H = 18.18 / 6.818 = 2.67

Multiply by 3 to express in whole number

C = 1 × 3 = 3

H = 2.67 × 3 = 8

Thus, the empirical formula of the compound is C₃H₈

Finally, we shall determine the molecular formula of the compound. This can be obtained as follow:

Molecular formula = Empirical formula × n = molar mass

[C₃H₈]n = 44

[(12×3) + (1×4)]n = 44

[36 + 4]n = 44

40n = 44

Divide both side by 40

n = 44/40

n ≈ 1

Molecular formula = C₃H₈ × n

Molecular formula = C₃H₈ × 1

Molecular formula = C₃H₈

Therefore, the molecular formula of the compound is C₃H₈

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