Answer:
x = 3 ± [tex]\sqrt{24}[/tex]
or
x = 3 + [tex]\sqrt{24}[/tex], x = 3 - [tex]\sqrt{24}[/tex]
Step-by-step explanation:
given f(x) = 2(x - 3)^2 - 8, find when f(x) = 40
So, we plug in 40 for f(x) in the 1st equation and solve for x. (Aim to got x on its own)
40 = 2 (x - 3)^2 - 8
+ 8 + 8
-----------------------------
48 = 2 (x - 3)^2
/2 /2
-----------------------------
24 = (x - 3)^2
square root both sides
--------------------
[tex]\sqrt{24}[/tex] = x - 3
x = 3 ± [tex]\sqrt{24}[/tex]
