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Triangle PQR is transformed to triangle P′Q′R′. Triangle PQR has vertices P(8, 0), Q(6, 2), and R(−2, −4). Triangle P′Q′R′ has vertices P′(4, 0), Q′(3, 1), and R′(−1, −2).

Plot triangles PQR and P′Q′R′ on your own coordinate grid.

Part A: What is the scale factor of the dilation that transforms triangle PQR to triangle P′Q′R′? Explain your answer. (4 points)

Part B: Write the coordinates of triangle P′′Q′′R′′ obtained after P′Q′R′ is reflected about the y-axis. (4 points)

Part C: Are the two triangles PQR and P′'Q′'R′' congruent? Explain your answer.

Respuesta :

yrj8498

Answer:

Transformation include reflecting and dilating of points

The scale factor from PQR to P'Q'R' is 1/4

The coordinates of P"Q"R" are P"=(-1,0) Q"=(0,-1)  R"=(2,-1)           .

PQR and P′'Q′'R′' are not congruent

The points are given as:

p=(4,0)

q=(0,-4)

r=(-8,-4)

p'=(1,0)

q'=(0-1)

r'=(-2,-1)

(a)The scale factor from PQR to P'Q'R

To do this, we make use of corresponding sides QR and Q'R

So, the scale factor (k) is:

k=q'r'/qr

k=2/8

k=1/4

(b) The coordinates of P"Q"R from reflecting P'Q'R' about the y-axis

The rule of this transformation is:

(x,y)--------(-x,y)

So, we have:

p"=(-1,0)

q"=(0,-1)

r"=(2,-1)

(c) Are triangle PQR and P"Q'R" congruent?

No they are not

This is so because

PQR was dilated by 1/4 to get P'Q'R

P'Q'R' and P"Q"R" are congruent

Hence,  PQR and P′'Q′'R′' are not congruent

Step-by-step explanation:

hussony492
Answer Transformation include reflecting and dilating of points

The scale factor from PQR to P'Q'R' is

1/4

The coordinates of P"Q"R" are P"=(-1,0) Q" (0,-1) R"=(2,-1)

PQR and P'Q"R" are not congruent

The points are given as:

p=(4,0)

q=(0,-4)

r=(-8,-4)

p'=(1,0)

q'=(0-1)

r'=(-2,-1)

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