You’ll have to solve for each slope to know the type of slopes of each pair of coordinates. Use the slope formula:
m = (y2 - y1)/(x2 - x1)
1.) (16, 3) (16, -80)
Let (x1, y1) = (16, 3)
(x2, y2) = (16, -80)
Substitute these values in the formula:
m = (y2 - y1)/(x2 - x1)
m = (-80 - 3)/(16 - 16)
m = -83/0
Since the denominator of the slope is 0, then it means that it is a UNDEFINED SLOPE of a vertical line along the x-intercept (a, 0), x = a. A vertical line has undefined slope because all points the line have the same x-coordinate.
2.) (0, 4.25)(1.25, 1.75)
m = (y2 - y1)/(x2 - x1)
m = (1.75 - 4.25)/(1.25 - 0)
m = -2.5/1.25
m = -2
As you can see, it is a NEGATIVE SLOPE.
3.) (-5, -20)(-11,-20)
m = (y2 - y1)/(x2 - x1)
m = [-20 - (-20)] / [-11 - (-5)]
m = (-20 + 20) / (-11 + 5)
m = 0/- 6
m = 0
It is a ZERO slope of a horizontal line, y =
b.
4) (-1000, 2500) (500, 4000)
m = (y2 - y1)/(x2 - x1)
m = (4000 - 2500)/[500 - (-1000)]
m = 1500/(500 + 1000)
m = 1500/1500
m = 1
A slope of m = 1 is a POSITIVE SLOPE.
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