Answer:
[tex]y = 3 {x}^{3} + 2 = = > y = \sqrt[3]{ \frac{(x - 2)}{3} } [/tex]
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[tex]y = 3 {x}^{2} - 2 = = > y = \frac{ + }{} \sqrt{ \frac{(x + 2)}{3} } [/tex]
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[tex]y = 2 {x}^{2} + 3 = = > y = \frac{ + }{} \sqrt{ \frac{(x - 3)}{2} } [/tex]
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[tex]y = 2 {x}^{3} - 3 = = > y = \sqrt[3]{ \frac{(x + 3)}{2} } [/tex]
I hope I helped you^_^
