Esther dives off a 3m springboard and initially bounces up with a velocity of 8.0 m/s at an angle of 80.0 to the horizontal.. what are the horizontal and vertical components of her velocity​

Respuesta :

This question involves the concept of the resolution of a vector into its rectangular components.

The horizontal component of velocity is "1.4 m/s", and the vertical component of the velocity is "7.9 m/s".

In order to find the horizontal and vertical components of the velocity of Esther, we must resolve the velocity vector into its rectangular components. Hence, the following formulae will be used:

[tex]Horizontal\ Component = v_x = v\ Cos\theta\\v_x = (8\ m/s)(Cos\ 80^o)\\v_x = 1.4\ m/s[/tex]

[tex]Vertical\ Component = v_y = v\ Sin\theta\\v_y = (8\ m/s)(Sin\ 80^o)\\v_y = 7.9\ m/s[/tex]

Learn more about the resolution of a vector here:

https://brainly.com/question/11234810?referrer=searchResults

The attached picture shows the resolution of a vector.

Ver imagen hamzaahmeds