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A line passes through the points (1, 4) and (3, –4). Which is the equation of the line? y = negative 4 x + 8 y = –2x + 6 y = negative one-foA line passes through the points (1, 4) and (3, –4). Which is the equation of the line? y = negative 4 x + 8 y = –2x + 6 y = negative one-fourth x + 2 y = 2x + 2urth x + 2 y = 2x + 2

Respuesta :

chetankachana

Answer:

y = -4x + 8

Step-by-step explanation:

The equation of a line is written in slope-intercept form : y = mx+b

m is the slope

We are given two points, so let's find the slope of the line first:

Slope = ΔY/ΔX = 4 - (-4) / 1 - 3 = 8 / -2 = -4

The slope is -4

So far, our equation is y = -4x + b

We can input a point's x and y value to find b, the y-intercept

Let's use point (1, 4)

4 = -4(1) + b

4 = -4 + b

b = 4 + 4

b = 8

The equation is y = -4x + 8

-Chetan K

Answer:

the answer is A

Step-by-step explanation:

y=-4x+8

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