contestada

What is the equation written in vertex form of a parabola with a vertex of (9, -1) that passes through (7. 7)?
O
A. y = 2(x - 992 - 1
B. y = 2(x + 1)2 - 9
O C. y = 2(x - 7)2 + 7
D. y = 7(x - 9)2 - 1

Respuesta :

Answer:

[tex]y = 2\, (x - 9)^{2} - 1[/tex].

Step-by-step explanation:

If the vertex of a parabola is [tex](h,\, k)[/tex], there would exist a constant [tex]a[/tex] ([tex]a \ne 0[/tex]) such that the following would be an equation for this parabola:

[tex]y = a\, (x - h)^{2} + k[/tex].

The equation above is in the vertex form.

In this question, the vertex of this parabola is [tex](9,\, -1)[/tex]. (Such that [tex]h = 9[/tex] and [tex]k = -1[/tex].) Therefore, the equation of this parabola in the vertex form would be:

[tex]\text{$y = a\, (x - 9)^{2} + (-1)$ for some $a \ne 0$}[/tex].

It was also given that the point [tex](7,\, 7)[/tex] is on the parabola. In other words, if [tex]x = 7[/tex] and [tex]y = 7[/tex], the equation of this parabola ([tex]\text{$y = a\, (x - 9)^{2} + (-1)$}[/tex]) should be satisfied. In other words:

[tex]7= a\, (7 - 9)^{2} + (-1)[/tex].

Solve this equation for [tex]a[/tex].

[tex]a = 2[/tex].

Therefore, the equation of this parabola in vertex form would be[tex]y = 2\, (x - 9) + (-1)[/tex], which is equivalently [tex]y = 2\, (x - 9)^{2} - 1[/tex].