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3 2. Write the equation of a line that includes the point (-4, 0) and has a slope of 5 in slope-intercept form- 12 3 y=-=X-2 5 5 3 Y= -=X - 12 O 3 y=-=X-5 12 y=-=X+​

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wegnerkolmp2741o

Answer:

y= 5x+20

Step-by-step explanation:

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

The slope is 5 and a point on the line is (-4,0)

Substituting this information into the equation, we can solve for b

0 = 5(-4) +b

0 = -20+b

Add 20 to each side

0+20 = -20+20+b

20 = b

y = 5x+20

DᴀʀᴋPᴀʀᴀᴅᴏx

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Let's find the y - intercept (c) of the line, by Plugging the value of x and y from coordinates of the given point (-4 , 0) and slope (m) = 5 :

  • [tex]y = mx + c[/tex]

  • [tex]0 = (5 \times (- 4)) + c[/tex]

  • [tex]0 = - 20 + c[/tex]

  • [tex]c = 20[/tex]

now, let's plug the value of slope (m) and y - intercept (c) in general equation of line to find the equation of line will have been asked for.

  • [tex]y = mx + c[/tex]

  • [tex]y = 5x + 20[/tex]

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