Answer:
[tex](2,1)[/tex]
Step-by-step explanation:
You can just use the formula [tex]x=-\frac{b}{2a}[/tex]:
[tex]y=ax^2+bx+c[/tex]
[tex]y=\frac{1}{2}x^2-2x+3[/tex]
[tex]x=-\frac{-2}{2(\frac{1}{2})}=\frac{2}{1}=2[/tex]
[tex]y=\frac{1}{2}(2)^2-2(2)+3=\frac{1}{2}(4)-4+3=2-4+3=-2+3=1[/tex]
Therefore, the minimum value of the equation is [tex](2,1)[/tex]
