Step-by-step explanation:
So you're going to try to always make the equation be in a y= mx +b point slope form. It just makes creating a graph easier.
First, we're going to put x to the opposite side so it's in the y= mx + b form. Remember that every time you cross the equal sign you do the opposite -[tex]x^{2}[/tex] turns into + [tex]x^{2}[/tex].
y- [tex]x^{2}[/tex] = -1 becomes y = [tex]x^{2}[/tex] -1.
Now all you have to do is plug in values. I recommend you start off small, so they can fit in your graph.
An example would be x = 2 now you plug in to find y which is [tex]2^{2}[/tex] = 4 -1 = 3. So you graph the point (2, 3).
To find the x- intercept and y- intercept you need to plug in 0. For the y-intercept, plug in 0 for x, since you're trying to find the y.
y = [tex]0^{2}[/tex] - 1. The y-intercept is -1 or the point (0, -1)
For the x-intercept, plug in 0 for y, since you're trying to find the x.
0 = [tex]x^{2}[/tex] -1 . Because you're trying to find x, you need to isolate x. Move -1 to the other side. Again, remember since you're moving across the = sign it changes to be positive. 1 = [tex]x^{2}[/tex]. To get rid of squared, you're going to have to square root it. [tex]\sqrt{x^2}[/tex] = x and [tex]\sqrt{1}[/tex] = 1. So the x- intercept is 1 or the point (1, 0).
To make the graph, know that the y axis is vertical (up and down) and the x axis is horizontal (left right). So, the point (0,0) would be on the bottom left corner.
