You buy 50 feet of fence to place around a rectangular yard. If the length of the yard is 13 feet, what is the constraint for the width of the yard? Let w represent width *

Respuesta :

Step-by-step explanation:

a fence represents the circumference, the perimeter of the lot or yard.

remember, a rectangle has 2 parallel sides called the length, and 2 parallel sides called the width (altogether 4 sides).

therefore

perimeter = 2×length + 2×width

or with short variables

p = 2×l + 2×w

so, now we have 50 ft of fence available for the perimeter. and the length l = 13 ft.

since we have 2 lengths in the perimeter, these 13 ft are twice (2×13 = 26 ft) in the perimeter.

now, how much fence do we have left for the width ?

well, 50 - 26 = 24 ft

and again, this is the size of 2 sides (2×width) :

p = 2×l + 2×w

50 = 2×13 + 2×w = 26 + 2×w

2×w = 24

w = 12 ft

so, the width of the yard must not be bigger than 12 ft.