It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.
From the question given above, the following data were obtained:
Height (H) = 206 m
Time (t) =?
NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the ball to get to the ground can be obtained as follow:
H = ½gt²
206 = ½ × 10 × t²
206 = 5 × t²
Divide both side by 5
[tex]t^{2} = \frac{206}{5}\\\\ t^{2} = 41.2[/tex]
Take the square root of both side
[tex]t = \sqrt{41.2}[/tex]
t = 6.42 s
Therefore, it will take 6.42 s for the ball to get to the ground.
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