Respuesta :
Answer:
117,30m
Explanation:
I think the situation here is a horizontal projection to the ground. So in order to find the distance the formula = Ut, where U is the initial speed and t is the Time of flight. To get the time of flight in this case =√2h/g where h is the height and g is gravity. so to get the time = √2×300÷9.81 =7.821 .so range =ut which is equal to the time multiplied by 15m/s =117.30m
Hi there!
To find the total distance traveled, we must find the time taken to fall down.
Ignore the horizontal velocity when dealing with the vertical direction. We can use the simplified equation:
[tex]t = \sqrt{\frac{2h}{g}{}}[/tex]
Plug in the given values:
[tex]t = \sqrt{\frac{2(300)}{9.81}} = 7.821 sec[/tex]
Use the equation:
Δd = vt
Plug in the time and horizontal velocity:
Δd = (15)(7.821) = 117.30m