Jason throws a ball horizontally off a 300 meter cliff at 15.0 m/s. How far will it travel before it hits the
ground? Use significant figures, and estimate g to be equal to 9.81 m/s2. Round the answer to the nearest
hundredth.
117.30 m
B
130.80 m
с
51.80 m
D
101.70 m

Respuesta :

Answer:

117,30m

Explanation:

I think the situation here is a horizontal projection to the ground. So in order to find the distance the formula = Ut, where U is the initial speed and t is the Time of flight. To get the time of flight in this case =√2h/g where h is the height and g is gravity. so to get the time = √2×300÷9.81 =7.821 .so range =ut which is equal to the time multiplied by 15m/s =117.30m

leena

Hi there!

To find the total distance traveled, we must find the time taken to fall down.

Ignore the horizontal velocity when dealing with the vertical direction. We can use the simplified equation:

[tex]t = \sqrt{\frac{2h}{g}{}}[/tex]

Plug in the given values:

[tex]t = \sqrt{\frac{2(300)}{9.81}} = 7.821 sec[/tex]

Use the equation:

Δd = vt

Plug in the time and horizontal velocity:

Δd = (15)(7.821) = 117.30m