Answer: if doing it on ck-12 the answer is 40.1
Explanation:
There are produced 40.1 grams of ammonium chloride (NH₄Cl) in the reaction between 17.0 g of ammonia (NH₃) and 26.6 g of chlorine gas (Cl₂).
The reaction between ammonia and chlorine gas is the following:
8NH₃ + 3Cl₂ → 6NH₄Cl + N₂
Initially, we have:
According to the conservation of mass, matter cannot be created or destroyed, only can be transformed, so the mass of the reactants must be equal to the mass of the products.
The mass of ammonium chloride produced is:
[tex] m_{r} = m_{p} [/tex]
[tex] m_{NH_{3}} + m_{Cl_{2}} = m_{NH_{4}Cl} + m_{N_{2}} [/tex]
[tex] 17.0 g + 26.6 g = m_{NH_{4}Cl} + 3.50 g [/tex]
[tex] m_{NH_{4}Cl} = 17.0 g + 26.6 g - 3.50 g = 40.1 g [/tex]
Therefore, 40.1 grams of ammonium chloride are produced in the reaction.
Learn more here:
I hope it helps you!
