Hi there!
On a horizontal circular track with friction, the net force acting in the horizontal direction is:
∑F = Fκ, or the force of kinetic friction.
We know that ΣF = Mv²/r, so:
Mv²/r = Fκ
Plug in the given values to solve:
(1750)(35²)/80 = Fκ
Thus:
Fκ = 26796.875 N
