Respuesta :

RevyBreeze

Answer:

A 925 kg car accelerates uniformly from rest to a velocity of 25.0 mls south in 10.0 s. What is the net force acting on the car during this time?

F=(925*25)/10

F=2312.5 N to south

leena

Hi there!

We can begin by calculating the acceleration experienced by the car.

vf = vi + at

The initial velocity is 0 (at rest), so:

25 = at

25/10 = a = 2.5 m/s²

Using Newton's Second Law:

∑F = ma, where:

∑F = net force (N)

m = mass (kg)

a = acceleration (m/s²)

Plug in the values:

∑F = 925 · 2.5 = 2312.5 N

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