Brainliest Question!!
Q1.) 5929 students are sitting in an auditorium in such a manner that there as are many students in a row as there are rows in the auditorium. How many rowsare there in the auditorium?

Let us suppose the the number of rows be x. Then, the number of number of students in each row becomes x as there are as many students in a row as there are rows in the auditorium.

Now, we have to simply frame a linear equation to tackle this question. Total number of the students will be equal to the product of number of students in each row and the number of rows.

Writing it in the form of a linear equation,

[tex] \longrightarrow \sf{\quad {5929 = x \times x}} \\ [/tex]

As there are 5929 students sitting in the auditorium.

[tex] \longrightarrow \sf{\quad {5929 = x^2}} \\ [/tex]

Now, put the square root symbol on both sides.

[tex] \longrightarrow \sf{\quad {\sqrt{5929} = \sqrt{x^2}}} \\ [/tex]

Square root of x² is x since x × x is x².

[tex] \longrightarrow \sf{\quad {\sqrt{5929} = x }} \\ [/tex]

Now, we have to find the value of √5929. By prime factorisation, 5929 = 7 × 7 × 11 × 11, make the pairs of the common factors and their product will be the square root of 5929 that is √5929 = 7 × 11 = 77.

[tex] \longrightarrow \quad\underline{\boxed{ \pmb{\frak{77 = x}} }} \\ [/tex]

Therefore, there are 77 rows in the auditorium.

Brainliest Question!!Q1.) 5929 students are sitting in an auditorium in such a manner that there as are many students in a row as there are rows in the auditorium. How many rowsare there in the auditorium?​

Respuesta :

Explanation:

Otras preguntas

Brainliest Question!!
Q1.) 5929 students are sitting in an auditorium in such a manner that there as are many students in a row as there are rows in the auditorium. How many rowsare there in the auditorium?