Use quadratic regression to find
the equation of the parabola
going through these 3 points.
(-1,23), (1,-5), (3,-57)
y = [ ? ]x2 + [ ]x+ [ ]
Enter

Respuesta :

Based on the information given, the required equation of parabola will be y= -3x² - 14x + 12.

Solution

The parabola passes through the points (-1, 23), (1, -5), (3, -57). Let the equation of the parabola be y = ax² + bx + c.

For point (-1, 23), this will be:

23 = a(-1)² + b(-1) + c

23 = a - b + c ..... equation i

For point (1, -5), this will be:

-5 = a(1)² + b(1) + c

-5 = a + b + c .... equation ii

For point (3, -57), this will be:

-57 = a(3)² + b(3) + c

-57 = 9a + 3b + c .... equation iii

From equation i, 23 = a - b + c

Therefore, c = 23 - a + b .... equation iv

Substitute c into equation ii

-5 = a + b + 23 - a + b

-5 = 2b + 23

2b = -23 - 5.

2b = -28

b = -28/2 = -14

Substitute c into equation iii

-57 = 9a + 3b + 23 - a + b

-80 = 8a + 4b.

-80 = 8a + 4(-14)

-80 = 8a - 56

8a = -80 + 56

8a = -24

a = -24/8 = -3

Therefore, the value of c will be:

c = 23 - a + b

c = 23 -(-3) + (-14)

c = 23 + 3 - 14

c = 12

In conclusion, the required equation of parabola will be y = -3x² - 14x + 12.

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