You toss a tennis ball straight upward. At the moment it leaves your hand it is at a height of 1.5 m above the ground, and it is moving at a speed of 7.0 m/s.

(a) How much time does it take for the tennis ball to reach its maximum height? (s)

(b) What is the maximum height above the ground that the tennis ball reaches? (m)

(c) When the tennis ball is at a height of 2.4 m above the ground, what is its speed? (m/s)

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snehashish65 snehashish65 · Answer 1 · 2022-06-28T18:55:19+02:00

a). 1.2 s

b). 3.81 m

c) v= 6.8 m/s

d) v= 27.05 m/s

Speed is define as the distance per unit time. It is also define as how fast an object is moving.

According to the question:

Height = 1.5 m , speed = 7.0 m/s.

a)By using 1st equation of motion

[tex]V = V_{0} + g*t.\\V = 0 \\V_{0} = 7.0 m/s.g = -9.8 m/s^2\\0 = 7 + (-9.8 m/s^2)*t\\t = 1.2 s[/tex]

b.

[tex]h = 1.5 + V_{0} *t + 0.5g*t^2\\V_{0} = 7.8 m/s\\t = 1.2s , g = -9.8 m/s^2\\h = 3.81 m[/tex]

c.

[tex]V^2 = V_{0} ^2 + 2g*d\\V_{0} = 7.8 m/s\\g= -9.8 m/s^2.\\d= 2.2-1.5 = 0.7 m\\V = 6.8 m/s[/tex]

d.

[tex]V^2 = V_{0} ^2 + 2g*h\\V_{0} = 0\\g = +9.8 m/s^2.\\h = 6.8 m\\V = 27.05 m/s[/tex]

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