Answer:
Step-by-step explanation:
(t-3)^5 is the same as (t + (-3))^5
First: t starts at the highest power and goes down and (-3) starts at the lowest power and goes up
Second: from the Pascal triangles take the coefficients 1 5 10 10 5 1
[tex]1*t^{5} (-3)^{0} + 5*t^{4} (-3)^{1} +10*t^{3} (-3)^{2} +10*t^{2} (-3)^{3} +5*t^{1} (-3)^{4} +1*t^{0} (-3)^{5}[/tex]
Anything to power 0 is equal to 1
Negative number to an odd power is negative, to a even power is positive
[tex]t^{5} -15t^{4} +90t^{3} -270t^{2} +405t -243[/tex]
