Question:-
Solve the following:
[tex] \\ \sf \: a) \: \: \frac{a}{5} + 3 = 8[/tex]
[tex] \\ \sf \: b) \: \: \frac{3b}{7} - 1 = 5[/tex]
Solution:-
Solving question a) :
[tex] \\ \sf \frac{a}{5 } + 3 = 8[/tex]
[tex] \\ \sf \mapsto \frac{a + 15}{5} = 8[/tex]
[tex] \\ \sf \mapsto \: a + 15 = 8 \times 5[/tex]
[tex] \\ \sf \mapsto \: a = 40 - 15[/tex]
[tex] \\ \sf \mapsto \: a = 25[/tex]
[tex] \\ \sf \therefore \: a = 25[/tex]
Solving question b) :
[tex] \\ \sf \frac{3b}{7} - 1 = 5[/tex]
[tex] \\ \sf \mapsto \: \frac{3b - 7}{7} = 5 [/tex]
[tex] \\ \sf \mapsto3b - 7 = 5 \times 7[/tex]
[tex] \\ \sf \mapsto3b = 35 + 7[/tex]
[tex] \\ \sf \mapsto \: b = \frac{42}{3} [/tex]
[tex] \\ \sf \mapsto \: b = 14[/tex]
[tex] \\ \sf \therefore \: b = 14[/tex]
Answer:-
a = 25
b = 14
