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State the equation of the line described.
A line passes through the point (-2,8) and is perpendicular to the line y = -3x + 3.


thank you guys!

Respuesta :

sheimaalgalham

Answer:

y = mx + b

Since it is perpendicular to the given line, its slope is the negative reciprocal of the slope of the given line.

Slope of given line:

m0 = -a/b = -(-3) / (1) = 3

Slope of perpendicular line:

m = -1/3

y = (-1/3)x + b

Use the given point to find b.

2 = (-1/3)(3) + b

2 = -1 + b

b = 3

y = (-1/3)x + 3

Step-by-step explanation:

s1m1

Answer:

Step-by-step explanation:

Perpendicular lines have their slope negative reciprocal

y= -3x +3 has the slope -3

y = (1/3)x +b is the line that is ⊥ so it has the slope (1/3)

The line passes trough the point (x=-2, y=8) so substitute the x and y to find b

8 = (1/3)(-2) +b, multiply (1/3)(-2) = -2/3 and add 2/3 on both sides

8+(2/3) = b, find the common denominator and add the fractions

[(3*8)+2 ]/3 =b

(26/3)  = b

The equation of the line described is y= (1/3)x +(26/3)

Ver imagen s1m1

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