NEED HELP PLEASE

Complete the table to find the pattern in the number of combinations.


Row 0 0C0 = 1

Row 1 1C0 = 1 1C1 = 1

Row 2 2C0 = 1 2C1 = ? 2C2 = 1

Row 3 3C0 = 1 3C1 =? 3C2 = ? 3C3 = 1

Row 4 4C0 = 1 4C1 = ? 4C2 = ? 4C3 =? 4C4 = 1

NEED HELP PLEASEComplete the table to find the pattern in the number of combinationsRow 0 0C0 1Row 1 1C0 1 1C1 1 Row 2 2C0 1 2C1 2C2 1 Row 3 3C0 1 3C1 3C2 3C3 1 class=

Respuesta :

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The formula for nCk is ...

  nCk = n!/(k!(n -k)!)

It always works out that nC0 = 1 and nC1 = n, and the sequence of numbers across a row of the diagram is symmetrical about the center.

This means you only need to calculate one value to finish filling your diagram.

  4C2 = 4!/(2!(2!)) = (4·3)/(2·1) = 6

You will find the pattern to be ...

  each element in the diagram is the sum of the two above  it.

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