Hi there!
For this part, we can disregard the horizontal velocity because horizontal and vertical motion are INDEPENDENT.
We can used the simplified equation to solve for time:
[tex]t = \sqrt{\frac{2h}{g}}[/tex]
Where:
h = height
g = acceleration due to gravity (assume g = 10 m/s²)
Plug in given values:
[tex]t = \sqrt{\frac{2(50)}{10}} = \sqrt{10}[/tex]
t ≈3.162 sec