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The uniform movement allows finding the results for the helicopter displacement during the 10 s is: 700 m
Kinematics studies the motion of bodies, finding relationships between the position, velocity and acceleration of the body, in the special case that the acceleration is zero, it is called uniform motion and is described by the equation
[tex]v = \frac{\Delta s}{t}[/tex]
Where v is the average velocity, Ds is the displacement and t is the time
Δs = v t
They indicate that the average speed is 70 m / s and the travel time is t=10.0s
Let's calculate
Δs = 70 10.0
Δs = 700 m / s
In conclusion using the uniform movement we can find the results for the helicopter displacement is: 700 m
Learn more here: brainly.com/question/14355103
The magnitude of the helicopter's displacement is 700 meters.
Given the following data:
- Velocity = 70 m/s
- Time = 10 seconds.
To find the magnitude of the helicopter's displacement:
Velocity can be defined as the rate of change in displacement (distance) with time.
Also, velocity is a vector quantity and as a result of this, it has both magnitude and direction.
Mathematically, velocity is given by the formula;
[tex]Velocity = \frac{displacement}{time}[/tex]
Making displacement the subject of formula, we have:
[tex]Displacement = velocity[/tex] × [tex]time[/tex]
[tex]Displacement = 70[/tex] × [tex]10[/tex]
Displacement = 700 meters.
Therefore, the magnitude of the helicopter's displacement is 700 meters.
Read more: https://brainly.com/question/17742679