The acceleration of the bicycle during the motion before stopping is 7.29 m/s².
The time taken for the bicycle to stop is 2.98 s.
The average speed of the bicycle is 10.83 m/s.
The given parameters;
The acceleration of the bicycle is calculated ad follows;
v² = u² + 2as
where;
v is the final velocity of the bicycle after stopping = 0
0 = u² + 2as
-2as = u²
[tex]a = -\frac{u^2}{2s} \\\\a = \frac{(21.7)^2}{2\times 32.3} \\\\a = -7.29 \ m/^2\\\\|a| = 7.29 \ m/s^2[/tex]
The time taken for the bicycle to stop is calculated as;
v = u + at
0 = 21.7 - 7.29t
7.29t = 21.7
[tex]t = \frac{21.7}{7.29} \\\\t = 2.98 \ s[/tex]
The average speed of the bicycle is calculated as;
[tex]v = \frac{totla \ distance}{total \ time} \\\\v = \frac{32.3}{2.98} \\\\v = 10.83 \ m/s[/tex]
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